2003 AMC 12B 第 17 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

17.

log(xy3)=1\log(xy^3) = 1log(x2y)=1\log(x^2y) = 1, 求 log(xy)\log(xy)

If log(xy3)=1\log(xy^3) = 1 and log(x2y)=1,\log(x^2y) = 1, what is log(xy)?\log(xy)?

12-\dfrac{1}{2}

00

12\dfrac{1}{2}

35\dfrac{3}{5}

11

答案:D
知识点:对数方程组
难度评级:1540
解答:

X=logxX = \log xY=logyY = \log y,则 且 X+3Y=1X + 3Y = 1 2X+Y=1.2X + Y = 1.

解得 X=25X = \dfrac{2}{5}Y=15Y = \dfrac{1}{5}, 所以 log(xy)=X+Y=35. \log(xy) = X + Y = \frac{3}{5}.

因此,正确答案是 D

Let X=logxX = \log x and Y=logy.Y = \log y. Then X+3Y=1X + 3Y = 1 and 2X+Y=1.2X + Y = 1.

Solving gives X=25X = \dfrac{2}{5} and Y=15,Y = \dfrac{1}{5}, so log(xy)=X+Y=35. \log(xy) = X + Y = \frac{3}{5}.

Thus, the correct answer is D.

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