2025 AMC 12B Problem 17

Below is the professionally curated solution for Problem 17 of the 2025 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 12B solutions, or check the answer key.

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Concepts:Burnside’s Lemmacasework

Difficulty rating: 1980

17.

Each of the 99 squares in a 3×33 \times 3 grid is to be colored red, blue, or yellow in such a way that each red square shares an edge with at least one blue square, each blue square shares an edge with at least one yellow square, and each yellow square shares an edge with at least one red square. Colorings that can be obtained from one another by rotations and/or reflections are to be considered the same. How many different colorings are possible?

33

99

1212

1818

2727

Solution:

Each red square needs a blue neighbor, each blue a yellow, and each yellow a red, forcing all three colors to appear in an interlocking pattern. A systematic check gives 8484 valid colorings of the labeled grid. Under the 88 symmetries of the square, only two diagonal reflections fix any colorings — 66 each — so Burnside's lemma gives 18(84+6+6)=12\tfrac{1}{8}(84 + 6 + 6) = 12 distinct colorings.

Thus, the correct answer is C.

Problem 17 in Other Years