2009 AMC 12B Problem 17

Below is the professionally curated solution for Problem 17 of the 2009 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 12B solutions, or check the answer key.

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Concepts:basic probabilitycube geometrycasework

Difficulty rating: 1890

17.

Each face of a cube is given a single narrow stripe painted from the center of one edge to the center of its opposite edge. The choice of the edge pairing is made at random and independently for each face. What is the probability that there is a continuous stripe encircling the cube?

18\dfrac{1}{8}

316\dfrac{3}{16}

14\dfrac{1}{4}

38\dfrac{3}{8}

12\dfrac{1}{2}

Solution:

Each of the 66 faces has 22 equally likely stripe orientations, for 26=642^6 = 64 configurations.

An encircling stripe runs around one of the 33 pairs of opposite faces. Fixing such a band, the four faces it passes through must be aligned, with probability (12)4=116,\left(\dfrac{1}{2}\right)^4 = \dfrac{1}{16}, while the two remaining faces are free. The 33 possible bands are disjoint events, so the probability is 3116=316.3 \cdot \dfrac{1}{16} = \dfrac{3}{16}.

Thus, the correct answer is B.

Problem 17 in Other Years