2017 AMC 12A Problem 17

Below is the professionally curated solution for Problem 17 of the 2017 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12A solutions, or check the answer key.

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Concepts:roots of unitycomplex number

Difficulty rating: 1910

17.

There are 2424 different complex numbers zz such that z24=1.z^{24}=1. For how many of these is z6z^6 a real number?

00

44

66

1212

2424

Solution:

The 2424 solutions are the 2424th roots of unity, z=eπik/12z=e^{\pi i k/12} for k=0,1,,23.k=0,1,\ldots,23.

Then z6=eπik/2=coskπ2+isinkπ2,z^6=e^{\pi i k/2}=\cos\dfrac{k\pi}{2}+i\sin\dfrac{k\pi}{2}, which is real exactly when sinkπ2=0,\sin\dfrac{k\pi}{2}=0, i.e. when kk is even. There are 1212 even values of kk in the range.

Thus, the correct answer is D.

Problem 17 in Other Years