2000 AMC 12 第 18 题

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18.

NN 年的第 300300 天是星期二,N+1N + 1 年的第 200200 天也是星期二。那么 N1N - 1 年的第 100100 天是星期几?

In year N,N, the 300300th day of the year is a Tuesday. In year N+1,N + 1, the 200200th day is also a Tuesday. On what day of the week did the 100100th day of year N1N - 1 occur?

星期四

Thursday

星期五

Friday

星期六

Saturday

星期日

Sunday

星期一

Monday

答案:A
知识点:日期与时间模运算
难度评级:1870
解答:

NN 年第 300300 天到 N+1N + 1 年第 200200 天,若 NN 不是闰年,相隔 365300+200=265365 - 300 + 200 = 265 天。但 265=737+6265 = 7 \cdot 37 + 6,会落在星期一,而不是星期二。

所以 NN 是闰年,相隔 266=738266 = 7 \cdot 38 天,正好仍为星期二。因此 N1N - 1 年不是闰年。

N1N - 1 年第 100100 天比 NN 年第 300300 天早 365100+300=565365 - 100 + 300 = 565 天。因为 565=780+5565 = 7 \cdot 80 + 5, 所以那一天比星期二早 55 天,即星期四。

因此,正确答案是 A

From day 300300 of year NN to day 200200 of year N+1,N + 1, the number of days is 365300+200=265365 - 300 + 200 = 265 if NN is not a leap year. But 265=737+6,265 = 7 \cdot 37 + 6, which would land on a Monday, not a Tuesday.

So year NN is a leap year, and the gap is 266=738266 = 7 \cdot 38 days, giving a Tuesday as stated. It follows that year N1N - 1 is not a leap year.

The 100100th day of year N1N - 1 precedes the Tuesday on day 300300 of year NN by 365100+300=565365 - 100 + 300 = 565 days. Since 565=780+5,565 = 7 \cdot 80 + 5, that day is 55 weekdays before Tuesday, namely Thursday.

Thus, the correct answer is A.

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