2000 AMC 12 第 18 题

先试着解答 2000 AMC 12 第 18 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2000 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

18.

NN 年的第 300300 天是星期二,N+1N + 1 年的第 200200 天也是星期二。那么 N−1N - 1 年的第 100100 天是星期几?
In year N,N, the 300300th day of the year is a Tuesday. In year N+1,N + 1, the 200200th day is also a Tuesday. On what day of the week did the 100100th day of year N−1N - 1 occur?
星期四
Thursday
星期五
Friday
星期六
Saturday
星期日
Sunday
星期一
Monday
答案:A
知识点:日期与时间模运算
小提示:
两个日期在同一星期几,当且仅当它们之间相隔的天数是 77 的倍数。
Two dates fall on the same weekday exactly when the number of days between them is a multiple of 77
大提示:
用两个给定的星期二判断 N−1,N,N+1N - 1, N, N + 1 中哪一年是闰年。
Use the two given Tuesdays to decide which of N−1,N,N+1N - 1, N, N + 1 is a leap year
解答:
从 NN 年第 300300 天到 N+1N + 1 年第 200200 天,若 NN 不是闰年,相隔 365−300+200=265365 - 300 + 200 = 265 天。但 265=7⋅37+6265 = 7 \cdot 37 + 6,会落在星期一,而不是星期二。
所以 NN 是闰年,相隔 266=7⋅38266 = 7 \cdot 38 天,正好仍为星期二。因此 N−1N - 1 年不是闰年。
N−1N - 1 年第 100100 天比 NN 年第 300300 天早 365−100+300=565365 - 100 + 300 = 565 天。因为 565=7⋅80+5565 = 7 \cdot 80 + 5,所以那一天比星期二早 55 天,即星期四。
因此,正确答案是 A。
From day 300300 of year NN to day 200200 of year N+1,N + 1, the number of days is 365−300+200=265365 - 300 + 200 = 265 if NN is not a leap year. But 265=7⋅37+6,265 = 7 \cdot 37 + 6, which would land on a Monday, not a Tuesday.
So year NN is a leap year, and the gap is 266=7⋅38266 = 7 \cdot 38 days, giving a Tuesday as stated. It follows that year N−1N - 1 is not a leap year.
The 100100th day of year N−1N - 1 precedes the Tuesday on day 300300 of year NN by 365−100+300=565365 - 100 + 300 = 565 days. Since 565=7⋅80+5,565 = 7 \cdot 80 + 5, that day is 55 weekdays before Tuesday, namely Thursday.
Thus, the correct answer is A.
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.