1999 AMC 12 Problem 18

Below is the professionally curated solution for Problem 18 of the 1999 AMC 12, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 12 solutions, or check the answer key.

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Concepts:trigonometrylogarithmfunction

Difficulty rating: 1770

18.

How many zeros does f(x)=cos(logx)f(x) = \cos(\log x) have on the interval 0<x<1?0 \lt x \lt 1?

00

11

22

1010

infinitely many

Solution:

As xx ranges over (0,1),(0, 1), logx\log x ranges over all negative real numbers. The cosine function is zero at π2nπ\tfrac{\pi}{2} - n\pi for every positive integer n,n, all of which are negative, so ff has infinitely many zeros.

Thus, the correct answer is E.

Problem 18 in Other Years