2021 AMC 12B Fall 第 23 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

23.

从集合 {1,2,3,,30}\{1, 2, 3, \ldots, 30\} 中随机选出 55 个不同整数组成一个子集。这个子集中相邻整数对的平均个数是多少?(例如集合 {1,17,18,19,30}\{1, 17, 18, 19, 30\}22 对相邻整数。)

What is the average number of pairs of consecutive integers in a randomly selected subset of 55 distinct integers chosen from the set {1,2,3,,30}?\{1, 2, 3, \ldots, 30\}? (For example the set {1,17,18,19,30}\{1, 17, 18, 19, 30\} has 22 pairs of consecutive integers.)

23\dfrac{2}{3}

2936\dfrac{29}{36}

56\dfrac{5}{6}

2930\dfrac{29}{30}

11

答案:A
知识点:期望值无放回抽样
难度评级:2190
解答:

2929 个相邻对中的每一对 (i,i+1)(i, i+1),设指标变量在两数都被选中时为 11。这个事件的概率为 530429=287\dfrac{5}{30} \cdot \dfrac{4}{29} = \dfrac{2}{87}

由期望的线性性,相邻整数对的期望数为 29287=2329 \cdot \dfrac{2}{87} = \dfrac{2}{3}

所以正确答案是 A

For each of the 2929 adjacent pairs (i,i+1),(i, i+1), let an indicator be 11 if both are in the subset. The probability of this is 530429=287.\dfrac{5}{30} \cdot \dfrac{4}{29} = \dfrac{2}{87}.

By linearity of expectation, the expected number of consecutive pairs is 29287=23.29 \cdot \dfrac{2}{87} = \dfrac{2}{3}.

Thus, the correct answer is A.

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