2018 AMC 12B Problem 23

Below is the professionally curated solution for Problem 23 of the 2018 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 12B solutions, or check the answer key.

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Concepts:3D geometryspherevector

Difficulty rating: 2400

23.

Ajay is standing at point AA near Pontianak, Indonesia, 00^\circ latitude and 110110^\circ E longitude. Billy is standing at point BB near Big Baldy Mountain, Idaho, USA, 4545^\circ N latitude and 115115^\circ W longitude. Assume that Earth is a perfect sphere with center C.C. What is the degree measure of ACB?\angle ACB?

105105

11212112\tfrac{1}{2}

120120

135135

150150

Solution:

The longitudes differ by 360(110+115)=135,360^\circ-(110^\circ+115^\circ)=135^\circ, and BB is at latitude 4545^\circ N. Place A=(1,0,0)A=(1,0,0) on the unit sphere.

Then B=(cos45cos135, cos45sin135, sin45)=(12,12,22).B=\left(\cos45^\circ\cos135^\circ,\ \cos45^\circ\sin135^\circ,\ \sin45^\circ\right)=\left(-\tfrac12,\tfrac12,\tfrac{\sqrt2}{2}\right). The dot product is AB=12,A\cdot B=-\tfrac12, so cosACB=12\cos\angle ACB=-\tfrac12 and ACB=120.\angle ACB=120^\circ.

Thus, the correct answer is C.

Problem 23 in Other Years