2000 AMC 12 第 16 题

先试着解答 2000 AMC 12 第 16 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2000 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

16.

一个 1313 行 1717 列的棋盘,每个方格中都写有一个数,从左上角开始编号,第一行编号为 11,22,…\ldots,1717,第二行编号为 1818,1919,…\ldots,3434,依此向下。如果重新编号,使左列从上到下为 11,22,…\ldots,1313,第二列为 1414,1515,…\ldots,2626,依此向右,有些方格在两种编号方式下得到相同的数。求这些方格中数字的和(任一种编号方式下都一样)。
A checkerboard of 1313 rows and 1717 columns has a number written in each square, beginning in the upper left corner, so that the first row is numbered 1,1, 2,2, …,\ldots, 17,17, the second row 18,18, 19,19, …,\ldots, 34,34, and so on down the board. If the board is renumbered so that the left column, top to bottom, is 1,1, 2,2, …,\ldots, 13,13, the second column 14,14, 15,15, …,\ldots, 2626 and so on across the board, some squares have the same numbers in both numbering systems. Find the sum of the numbers in these squares (under either system).
222222
333333
444444
555555
666666
答案:D
知识点:丢番图方程系统列举
小提示:
第 mm 行第 nn 列的方格原来编号为 17(m−1)+n17(m - 1) + n,重新编号后为 13(n−1)+m13(n - 1) + m。
The square in row m,m, column nn is numbered 17(m−1)+n17(m - 1) + n originally and 13(n−1)+m13(n - 1) + m after
大提示:
令两个表达式相等,得到 4m−3n=14m - 3n = 1;找出所有合法的 (m,n)(m, n)。
Setting the two expressions equal gives 4m−3n=14m - 3n = 1; find all valid (m,n)(m, n)
解答:
方格 (m,n)(m, n) 原来的编号为 17(m−1)+n17(m - 1) + n,重新编号后为 13(n−1)+m13(n - 1) + m。令它们相等,得 4m−3n=1。 4m - 3n = 1\text{。}
满足 1≤m≤131 \le m \le 13 且 1≤n≤171 \le n \le 17 的解为 (1,1)(1, 1),(4,5)(4, 5),(7,9)(7, 9),(10,13)(10, 13),和 (13,17)(13, 17)。
这些方格中的数为 1,56,111,1661, 56, 111, 166 和 221221,总和为 555555。
因此,正确答案是 D。
The square (m,n)(m, n) is numbered 17(m−1)+n17(m - 1) + n originally and 13(n−1)+m13(n - 1) + m after renumbering. Setting these equal gives 4m−3n=1. 4m - 3n = 1.
The solutions with 1≤m≤131 \le m \le 13 and 1≤n≤171 \le n \le 17 are (1,1),(1, 1), (4,5),(4, 5), (7,9),(7, 9), (10,13),(10, 13), and (13,17).(13, 17).
These squares hold the numbers 1,56,111,166,1, 56, 111, 166, and 221,221, whose sum is 555.555.
Thus, the correct answer is D.
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