2009 AMC 12A 第 19 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

19.

Andrea 在一个正五边形内切一个圆,并在该五边形外接一个圆,然后计算两个圆之间区域的面积。Bethany 对一个正七边形(77 条边)做了同样的事情。两个区域的面积分别为 AABB,每个多边形的边长都是 22。下列哪项正确?

Andrea inscribed a circle inside a regular pentagon, circumscribed a circle around the pentagon, and calculated the area of the region between the two circles. Bethany did the same with a regular heptagon (77 sides). The areas of the two regions were AA and B,B, respectively. Each polygon had a side length of 2.2. Which of the following is true?

A=2549BA = \dfrac{25}{49}B

A=57BA = \dfrac{5}{7}B

A=BA = B

A=75BA = \dfrac{7}{5}B

A=4925BA = \dfrac{49}{25}B

答案:C
知识点:正多边形勾股定理圆面积
难度评级:1910
解答:

对边长为 22 的正多边形,令 OO 为中心,MM 为一条边的中点,NN 为该边的一个端点。那么 OMN\triangle OMNMM 处为直角,且 MN=1MN = 1OM=rOM = r(内切圆半径),ON=RON = R(外接圆半径)。

所以 R2r2=1R^2 - r^2 = 1, 两圆之间的面积为 π(R2r2)=π\pi(R^2 - r^2) = \pi,与边数无关。因此 A=BA = B

因此,正确答案是 C

For a regular polygon with side length 2,2, let OO be the center, MM the midpoint of a side, and NN an endpoint of that side. Then OMN\triangle OMN has a right angle at M,M, with MN=1,MN = 1, OM=rOM = r (inradius), and ON=RON = R (circumradius).

So R2r2=1,R^2 - r^2 = 1, and the area between the circles is π(R2r2)=π\pi(R^2 - r^2) = \pi for any number of sides. Hence A=B.A = B.

Thus, the correct answer is C.

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