2021 AMC 12B Fall Problem 19

Below is the professionally curated solution for Problem 19 of the 2021 AMC 12B Fall, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Fall solutions, or check the answer key.

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Concepts:regular polygoncounting intersections

Difficulty rating: 2320

19.

Regular polygons with 5,5, 6,6, 7,7, and 88 sides are inscribed in the same circle. No two of the polygons share a vertex, and no three of their sides intersect at a common point. At how many points inside the circle do two of their sides intersect?

5252

5656

6060

6464

6868

Solution:

For two convex polygons inscribed in the same circle with no shared vertices, each side of the smaller polygon crosses the larger polygon's boundary exactly twice, so they meet at 2min(m,n)2\min(m, n) points.

Summing over all pairs: (5,6),(5,7),(5,8)(5,6), (5,7), (5,8) give 1010 each; (6,7),(6,8)(6,7), (6,8) give 1212 each; (7,8)(7,8) gives 14.14.

The total is 310+212+14=68.3 \cdot 10 + 2 \cdot 12 + 14 = 68.

Thus, the correct answer is E.

Problem 19 in Other Years