2003 AMC 12B Problem 8

Below is the professionally curated solution for Problem 8 of the 2003 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 12B solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:digitscasework

Difficulty rating: 1390

8.

Let (x)\clubsuit(x) denote the sum of the digits of the positive integer x.x. For example, (8)=8\clubsuit(8) = 8 and (123)=1+2+3=6.\clubsuit(123) = 1 + 2 + 3 = 6. For how many two-digit values of xx is ((x))=3?\clubsuit(\clubsuit(x)) = 3?

33

44

66

99

1010

Solution:

Let y=(x).y = \clubsuit(x). Since x99,x \le 99, we have y18.y \le 18. Then (y)=3\clubsuit(y) = 3 requires y=3y = 3 or y=12.y = 12.

The two-digit numbers with digit sum 33 are 12,21,3012, 21, 30 (33 values), and those with digit sum 1212 are 39,48,57,66,75,84,9339, 48, 57, 66, 75, 84, 93 (77 values), for 1010 in all.

Thus, the correct answer is E.

Problem 8 in Other Years