2011 AMC 12A Problem 8

Below is the professionally curated solution for Problem 8 of the 2011 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 12A solutions, or check the answer key.

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Concepts:pattern recognitionalgebraic manipulation

Difficulty rating: 1190

8.

In the eight-term sequence A,B,C,D,E,F,G,H,A, B, C, D, E, F, G, H, the value of CC is 55 and the sum of any three consecutive terms is 30.30. What is A+H?A + H?

1717

1818

2525

2626

4343

Solution:

Since A+B+C=B+C+D=30,A + B + C = B + C + D = 30, we get D=A,D = A, and likewise the sequence repeats with period 3.3. Thus H,H, the eighth term, equals B.B.

From A+B+C=30A + B + C = 30 and C=5,C = 5, we have A+H=A+B=305=25.A + H = A + B = 30 - 5 = 25.

Thus, the correct answer is C.

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