2005 AMC 12B 第 8 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

对多少个 aa 的值,直线 y=x+ay = x + a 经过抛物线 y=x2+a2y = x^2 + a^2 的顶点?

For how many values of aa is it true that the line y=x+ay = x + a passes through the vertex of the parabola y=x2+a2?y = x^2 + a^2?

00

11

22

1010

无限多个

infinitely many

答案:C
知识点:抛物线二次方程
难度评级:1350
解答:

抛物线 y=x2+a2y = x^2 + a^2 的顶点为 (0,a2)(0, a^2)

直线 y=x+ay = x + a 经过该点当且仅当 a2=0+aa^2 = 0 + a,即 a2a=0a^2 - a = 0

所以 a=0a = 0a=1a = 1,共有 22 个值。

所以正确答案是 C

The vertex of the parabola y=x2+a2y = x^2 + a^2 is (0,a2).(0, a^2).

The line y=x+ay = x + a passes through it exactly when a2=0+a,a^2 = 0 + a, that is a2a=0.a^2 - a = 0.

This gives a=0a = 0 or a=1,a = 1, so there are 22 values.

Thus, the correct answer is C.

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