2021 AMC 12A Spring 第 6 题

先试着解答 2021 AMC 12A Spring 第 6 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2021 AMC 12A Spring 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

一副牌只有红牌和黑牌。随机抽到一张红牌的概率是 13\dfrac13。当向这副牌中加入 44 张黑牌后,抽到红牌的概率变为 14\dfrac14。这副牌原来有多少张牌?
A deck of cards has only red cards and black cards. The probability of a randomly chosen card being red is 13.\dfrac13. When 44 black cards are added to the deck, the probability of choosing red becomes 14.\dfrac14. How many cards were in the deck originally?
66
99
1212
1515
1818
答案:C
知识点:基本概率方程组
小提示:
设红牌数为 rr;原牌堆共有 3r3r 张牌
Let rr be the number of red cards; the original deck has 3r3r cards
大提示:
加入 44 张黑牌后,红牌仍为 rr 张,总数为 3r+43r + 4,且比例等于 14\dfrac14。
Adding 44 black cards keeps rr red out of 3r+4,3r + 4, and this equals 14\dfrac14
解答:
设红牌数为 rr,总牌数为 tt。由 rt=13\dfrac{r}{t} = \dfrac13 得 t=3rt = 3r。加入 44 张黑牌后,rt+4=14\dfrac{r}{t+4} = \dfrac14,所以 t+4=4rt + 4 = 4r。
代入 t=3rt = 3r 得 3r+4=4r3r + 4 = 4r,因此 r=4r = 4,t=12t = 12。
因此,正确答案是 C。
Let rr be the number of red cards and tt the total. From rt=13\dfrac{r}{t} = \dfrac13 we get t=3r.t = 3r. After adding 44 black cards, rt+4=14,\dfrac{r}{t+4} = \dfrac14, so t+4=4r.t + 4 = 4r.
Substituting t=3rt = 3r gives 3r+4=4r,3r + 4 = 4r, so r=4r = 4 and t=12.t = 12.
Thus, the correct answer is C.
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