1999 AMC 12 Problem 6

Below is the professionally curated solution for Problem 6 of the 1999 AMC 12, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 12 solutions, or check the answer key.

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Concepts:exponentdigits

Difficulty rating: 1170

6.

What is the sum of the digits of the decimal form of the product 2199952001?2^{1999} \cdot 5^{2001}?

22

44

55

77

1010

Solution:

Write 2199952001=219995199952=25101999, 2^{1999} \cdot 5^{2001} = 2^{1999} \cdot 5^{1999} \cdot 5^2 = 25 \cdot 10^{1999}, which is 2525 followed by 19991999 zeros. The sum of the digits is 2+5=7.2 + 5 = 7.

Thus, the correct answer is D.

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