2017 AMC 12A 第 10 题

先试着解答 2017 AMC 12A 第 10 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2017 AMC 12A 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

10.

Chloé 从区间 [0,2017][0,2017] 中均匀随机选择一个实数。Laurent 独立地从区间 [0,4034][0,4034] 中均匀随机选择一个实数。Laurent 选到的数大于 Chloé 选到的数的概率是多少?

Chloé chooses a real number uniformly at random from the interval [0,2017].[0,2017]. Independently, Laurent chooses a real number uniformly at random from the interval [0,4034].[0,4034]. What is the probability that Laurent's number is greater than Chloé's number?

12\dfrac{1}{2}

23\dfrac{2}{3}

34\dfrac{3}{4}

56\dfrac{5}{6}

78\dfrac{7}{8}

答案:C
知识点:几何概率对称性对立事件概率
难度评级:1560
解答:

Laurent 的数有概率 12\dfrac{1}{2} 落在 [2017,4034][2017,4034],这会大于 Chloé 可能选择的任何数,因此他必胜。

另有概率 12\dfrac{1}{2},Laurent 的数落在 [0,2017][0,2017],与 Chloé 的区间相同;由对称性,他较大的概率是一半。总概率为 121+1212=34. \dfrac{1}{2}\cdot1+\dfrac{1}{2}\cdot\dfrac{1}{2}=\dfrac{3}{4}.

所以正确答案是 C

With probability 12,\dfrac{1}{2}, Laurent's number lies in [2017,4034],[2017,4034], which exceeds any number Chloé could choose, so he wins for certain.

With the other probability 12,\dfrac{1}{2}, Laurent's number lies in [0,2017],[0,2017], matching Chloé's interval; by symmetry he is larger half the time. The total probability is 121+1212=34. \dfrac{1}{2}\cdot1+\dfrac{1}{2}\cdot\dfrac{1}{2}=\dfrac{3}{4}.

Thus, the correct answer is C.

← 第 9 题#9
完整试卷

其他年份的第 10 题