2016 AMC 12A Problem 10

Below is the professionally curated solution for Problem 10 of the 2016 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 12A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:invariantlogical deduction

Difficulty rating: 1410

10.

Five friends sat in a movie theater in a row containing 55 seats, numbered 11 to 55 from left to right. (The directions "left" and "right" are from the point of view of the people as they sit in the seats.) During the movie Ada went to the lobby to get some popcorn. When she returned, she found that Bea had moved two seats to the right, Ceci had moved one seat to the left, and Dee and Edie had switched seats, leaving an end seat for Ada. In which seat had Ada been sitting before she got up?

11

22

33

44

55

Solution:

The net displacement of all five friends is zero. Dee and Edie swapped seats, so their movements cancel. Bea moved +2+2 and Ceci moved 1,-1, a net of +1,+1, so Ada must move 1-1 to balance.

Ada returns to an end seat; since she moved one seat to the left, that seat must be seat 1,1, so she had been sitting in seat 2.2.

Thus, the correct answer is B.

Problem 10 in Other Years