2014 AMC 12A 第 8 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

一位顾客打算购买一件电器,有三张优惠券,但只能使用其中一张:

优惠券一:标价优惠 10%10\%,但标价须至少为 $50\$50

优惠券二:标价减 $20\$20,但标价须至少为 $100\$100

优惠券三:标价超过 $100\$100 的部分优惠 18%18\%

对下列哪个标价,优惠券一的降价幅度会同时大于优惠券二和优惠券三?

A customer who intends to purchase an appliance has three coupons, only one of which may be used:

Coupon 1: 10%10\% off the listed price if the listed price is at least $50\$50

Coupon 2: $20\$20 off the listed price if the listed price is at least $100\$100

Coupon 3: 18%18\% off the amount by which the listed price exceeds $100\$100

For which of the following listed prices will coupon 1 offer a greater price reduction than either coupon 2 or coupon 3?

$179.95\$179.95

$199.95\$199.95

$219.95\$219.95

$239.95\$239.95

$259.95\$259.95

答案:C
知识点:不等式百分数
难度评级:1440
解答:

当价格 P>100P\gt100 时,三张优惠券的降价金额分别为 P10\dfrac{P}{10}202018100(P100)\dfrac{18}{100}(P-100)

优惠券一优于优惠券二需要 P10>20\dfrac{P}{10}\gt20,即 P>200P\gt200。优惠券一优于优惠券三需要 P10>18100(P100)\dfrac{P}{10}\gt\dfrac{18}{100}(P-100),即 P<225P\lt225

所列价格中,只有 $219.95\$219.95 落在 (200,225)(200,225) 内。

所以正确答案是 C

For a price P>100,P\gt100, the reductions are P10,\dfrac{P}{10}, 20,20, and 18100(P100).\dfrac{18}{100}(P-100).

Coupon 1 beats coupon 2 when P10>20,\dfrac{P}{10}\gt20, that is P>200.P\gt200. Coupon 1 beats coupon 3 when P10>18100(P100),\dfrac{P}{10}\gt\dfrac{18}{100}(P-100), that is P<225.P\lt225.

The only listed price in (200,225)(200,225) is $219.95.\$219.95.

Thus, the correct answer is C.

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