2010 AMC 12B 第 6 题

先试着解答 2010 AMC 12B 第 6 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2010 AMC 12B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

学年开始时,Wells 老师数学班中 50%50\% 的学生对问题“你喜欢数学吗?”回答“喜欢”,50%50\% 回答“不喜欢”。学年结束时,70%70\% 回答“喜欢”,30%30\% 回答“不喜欢”。共有 x%x\% 的学生在学年开始和结束时给出了不同回答。xx 的最大可能值与最小可能值相差多少?
At the beginning of the school year, 50%50\% of all students in Mr. Wells’ math class answered “Yes” to the question “Do you love math”, and 50%50\% answered “No.” At the end of the school year, 70%70\% answered “Yes” and 30%30\% answered “No.” Altogether, x%x\% of the students gave a different answer at the beginning and end of the school year. What is the difference between the maximum and the minimum possible values of x?x?
00
2020
4040
6060
8080
答案:D
知识点:百分数极端原理
小提示:
假设有 100100 名学生;回答“喜欢”的人数从 5050 增加到 7070
Assume 100100 students; the “Yes” count rises from 5050 to 7070
大提示:
至少有 2020 人必须改变回答,而最终只有 3030 人回答“不喜欢”,这会限制最多有多少人改变回答
At least 2020 must switch, and only 3030 end with “No,” bounding how many can switch
解答:
假设有 100100 名学生。回答“喜欢”的人数从 5050 增加到 7070,所以至少有 70−50=2070-50=20 名学生从“不喜欢”改为“喜欢”;因此 x≥20x\ge20。
因为结束时只有 3030 名学生回答“不喜欢”,原来回答“喜欢”的五十人中至少有 50−30=2050-30=20 人仍回答“喜欢”,所以最多有 8080 名学生改变回答;因此 x≤80x\le80。
两个极端都可以实现,所以差为 80−20=6080-20=60。
因此,正确答案是 D。
Assume 100100 students. The number of “Yes” answers rises from 5050 to 70,70, so at least 70−50=2070-50=20 students switched from “No” to “Yes”; thus x≥20.x\ge20.
Since only 3030 students answer “No” at the end, at least 50−30=2050-30=20 of the original “Yes” students still answer “Yes,” so at most 8080 students switched; thus x≤80.x\le80.
Both extremes are achievable, so the difference is 80−20=60.80-20=60.
Thus, the correct answer is D.
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