2008 AMC 12B 第 10 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

10.

砌砖工 Brenda 单独建一个烟囱需要 99 小时,砌砖工 Brandon 单独建需要 1010 小时。他们一起工作时聊天很多,合计产出每小时减少 1010 块砖。他们一起工作 55 小时建完烟囱。这个烟囱有多少块砖?

Bricklayer Brenda would take 99 hours to build a chimney alone, and bricklayer Brandon would take 1010 hours to build it alone. When they work together, they talk a lot, and their combined output is decreased by 1010 bricks per hour. Working together, they build the chimney in 55 hours. How many bricks are in the chimney?

500500

900900

950950

10001000

19001900

答案:B
知识点:速率一次方程
难度评级:1530
解答:

设烟囱有 nn 块砖。Brenda 单独工作时每小时砌 n9\tfrac{n}{9} 块,Brandon 每小时砌 n10\tfrac{n}{10} 块。一起工作时,他们的效率为 n9+n1010\tfrac{n}{9} + \tfrac{n}{10} - 10

工作 55 小时完成烟囱,因此 展开得 5n9+5n1050=n\tfrac{5n}{9} + \tfrac{5n}{10} - 50 = n,所以 95n90n=50\tfrac{95n}{90} - n = 50,从而 5n90=50\tfrac{5n}{90} = 505(n9+n1010)=n. 5\left(\tfrac{n}{9} + \tfrac{n}{10} - 10\right) = n.

因此 n=900n = 900

因此,正确答案是 B

Let nn be the number of bricks. Alone, Brenda lays n9\tfrac{n}{9} bricks per hour and Brandon lays n10.\tfrac{n}{10}. Together, their rate is n9+n1010.\tfrac{n}{9} + \tfrac{n}{10} - 10.

Working for 55 hours completes the chimney: 5(n9+n1010)=n. 5\left(\tfrac{n}{9} + \tfrac{n}{10} - 10\right) = n. Expanding, 5n9+5n1050=n,\tfrac{5n}{9} + \tfrac{5n}{10} - 50 = n, so 95n90n=50,\tfrac{95n}{90} - n = 50, giving 5n90=50.\tfrac{5n}{90} = 50.

Hence n=900.n = 900.

Thus, the correct answer is B.

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