2001 AMC 12 第 8 题

先试着解答 2001 AMC 12 第 8 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2001 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

下面哪个圆锥可以由一个半径为 1010、圆心角为 252∘252^\circ 的扇形,把两条直边对齐后形成?
Which of the cones below can be formed from a 252∘252^\circ sector of a circle of radius 1010 by aligning the two straight sides?
答案:C
知识点:圆锥弧圆周长
小提示:
扇形的半径会成为圆锥的母线长,所以母线长是 1010
The radius of the sector becomes the slant height of the cone, so the slant height is 1010
大提示:
扇形的弧长会成为底面周长:252360⋅2π(10)\dfrac{252}{360}\cdot 2\pi(10)
The arc length of the sector becomes the base circumference: 252360⋅2π(10)\dfrac{252}{360}\cdot 2\pi(10)
解答:
当扇形卷成圆锥时,它的半径 1010 成为母线长,它的弧成为底面圆。
弧长为 252360⋅2π(10)=710⋅20π=14π, \dfrac{252}{360}\cdot 2\pi(10) = \dfrac{7}{10}\cdot 20\pi = 14\pi\text{,} 所以底面周长是 14π14\pi,底面半径是 77。
因此该圆锥的底面半径为 77,母线长为 1010,对应选项 C。
因此,正确答案是 C。
When the sector is rolled into a cone, its radius 1010 becomes the slant height, and its arc becomes the base circle.
The arc length is 252360⋅2π(10)=710⋅20π=14π, \dfrac{252}{360}\cdot 2\pi(10) = \dfrac{7}{10}\cdot 20\pi = 14\pi, so the base circumference is 14π14\pi and the base radius is 7.7.
The cone therefore has base radius 77 and slant height 10,10, which is choice C.
Thus, the correct answer is C.
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