2000 AMC 12 第 8 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

图形 0,1,20, 1, 233 分别由 1,5,131, 5, 132525 个互不重叠的单位正方形组成。如果继续这个规律,图形 100100 中会有多少个互不重叠的单位正方形?

Figures 0,1,2,0, 1, 2, and 33 consist of 1,5,13,1, 5, 13, and 2525 nonoverlapping unit squares, respectively. If the pattern were continued, how many nonoverlapping unit squares would there be in figure 100?100?

1040110401

1980119801

2020120201

3980139801

4080140801

答案:C
知识点:找规律完全平方数
难度评级:1370
解答:

图形 nn 是一个菱形,各行长度按奇数增大后再减小,所以共有 n2+(n+1)2n^2 + (n + 1)^2 个单位正方形。这与 n=0,1,2,3n = 0, 1, 2, 3 时的 1,5,13,251, 5, 13, 25 相符。

因此图形 100100 中单位正方形的个数为 个。 1002+1012=10000+10201=20201 \begin{aligned} 100^2 + 101^2 &= 10000 + 10201 \\ &= 20201 \end{aligned}

因此,正确答案是 C

Figure nn is a diamond whose row lengths increase through the odd numbers and back down, giving a total of n2+(n+1)2n^2 + (n + 1)^2 unit squares. This matches 1,5,13,251, 5, 13, 25 for n=0,1,2,3.n = 0, 1, 2, 3.

Therefore figure 100100 has 1002+1012=10000+10201=20201 \begin{aligned} 100^2 + 101^2 &= 10000 + 10201 \\ &= 20201 \end{aligned} unit squares.

Thus, the correct answer is C.

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