2021 AMC 12B Fall 第 6 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

16,38416{,}384 的最大质因数是 22,因为 16,384=21416{,}384 = 2^{14}16,38316{,}383 的最大质因数的数字和是多少?

The greatest prime number that is a divisor of 16,38416{,}384 is 22 because 16,384=214.16{,}384 = 2^{14}. What is the sum of the digits of the greatest prime number that is a divisor of 16,383?16{,}383?

33

77

1010

1616

2222

答案:C
知识点:平方差质因数分解
难度评级:1280
解答:

因为 16,383=214116{,}383 = 2^{14} - 1 =(271)(27+1)= (2^{7} - 1)(2^{7} + 1) =127129= 127 \cdot 129,而 129=343129 = 3 \cdot 43,所以 16,383=34312716{,}383 = 3 \cdot 43 \cdot 127

最大质因数是 127127,其各位数字之和为 1+2+7=101 + 2 + 7 = 10

所以正确答案是 C

Since 16,383=214116{,}383 = 2^{14} - 1 =(271)(27+1)= (2^{7} - 1)(2^{7} + 1) =127129.= 127 \cdot 129. Then 129=343,129 = 3 \cdot 43, so 16,383=343127.16{,}383 = 3 \cdot 43 \cdot 127.

The greatest prime factor is 127,127, whose digit sum is 1+2+7=10.1 + 2 + 7 = 10.

Thus, the correct answer is C.

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