2012 AMC 12A Problem 7

Below is the professionally curated solution for Problem 7 of the 2012 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 12A solutions, or check the answer key.

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Concepts:arithmetic sequenceoptimization

Difficulty rating: 1240

7.

Mary divides a circle into 1212 sectors. The central angles of these sectors, measured in degrees, are all integers and they form an arithmetic sequence. What is the degree measure of the smallest possible sector angle?

55

66

88

1010

1212

Solution:

Let aa be the smallest angle and d0d \ge 0 the common difference. The sum of the angles is 12a+66d=360,12a + 66d = 360, so 2a+11d=60.2a + 11d = 60.

To make aa small, take dd large. Since 11d11d must be even, dd is even, and d=4d = 4 gives 2a=6044=16,2a = 60 - 44 = 16, so a=8.a = 8. A larger even dd makes aa non-positive.

Thus, the correct answer is C.

Problem 7 in Other Years