2012 AMC 12B Problem 7

Below is the professionally curated solution for Problem 7 of the 2012 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 12B solutions, or check the answer key.

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Concepts:pattern recognitionunit conversion

Difficulty rating: 1270

7.

Small lights are hung on a string 66 inches apart in the order red, red, green, green, green, red, red, green, green, green, and so on continuing this pattern of 22 red lights followed by 33 green lights. How many feet separate the 33rd red light and the 2121st red light?

Note: 11 foot is equal to 1212 inches.

1818

18.518.5

2020

20.520.5

22.522.5

Solution:

The lights repeat in blocks of 5,5, so consecutive blocks start 56=305\cdot6=30 inches, or 2.52.5 feet, apart.

Each block has one odd-numbered red light beginning it. The 33rd red light begins the 22nd block and the 2121st red light begins the 1111th block.

The distance between them is (112)2.5=22.5(11-2)\cdot2.5=22.5 feet.

Thus, the correct answer is E.

Problem 7 in Other Years