2017 AMC 12B Problem 7

Below is the professionally curated solution for Problem 7 of the 2017 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12B solutions, or check the answer key.

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Concepts:trigonometric identityfunction

Difficulty rating: 1500

7.

The functions sin(x)\sin(x) and cos(x)\cos(x) are periodic with least period 2π.2\pi. What is the least period of the function cos(sin(x))?\cos(\sin(x))?

π2\dfrac{\pi}{2}

π\pi

2π2\pi

4π4\pi

It's not periodic.

Solution:

Since cos(sin(x+π))=cos(sin(x))=cos(sin(x)),\cos(\sin(x + \pi)) = \cos(-\sin(x)) = \cos(\sin(x)), the function has period π.\pi. It cannot be smaller: cos(sin(x))=1\cos(\sin(x)) = 1 exactly when sin(x)=0,\sin(x) = 0, which happens only at integer multiples of π,\pi, so the maxima are spaced π\pi apart. The least period is π.\pi.

Thus, the correct answer is B.

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