2011 AMC 12B 第 6 题

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6.

从点 AA 向一个圆作两条切线。切点 BBCC 将圆分成的两段弧长之比为 2:32:3BAC\angle BAC 的度数是多少?

Two tangents to a circle are drawn from a point A.A. The points of contact BB and CC divide the circle into arcs with lengths in the ratio 2:3.2:3. What is the degree measure of BAC?\angle BAC?

2424

3030

3636

4848

6060

答案:C
知识点:切线导角
难度评级:1240
解答:

OO 为圆心。两段弧分别为 2x2x3x3x,且 2x+3x=3602x+3x=360^\circ,所以 x=72x=72^\circ,小弧 BCBC 对应的圆心角为 BOC=144\angle BOC=144^\circ

到切点 BBCC 的半径垂直于切线,所以 ABO=ACO=90\angle ABO=\angle ACO=90^\circ。在四边形 ABOCABOC 中, BAC=3601449090=36. \begin{gathered} \angle BAC=360^\circ-144^\circ-90^\circ \\ {}-90^\circ=36^\circ. \end{gathered}

所以正确答案是 C

Let OO be the center. The arcs measure 2x2x and 3x3x with 2x+3x=360,2x+3x=360^\circ, so x=72x=72^\circ and the minor arc BCBC gives central angle BOC=144.\angle BOC=144^\circ.

The radii to BB and CC are perpendicular to the tangents, so ABO=ACO=90.\angle ABO=\angle ACO=90^\circ. In quadrilateral ABOC,ABOC, BAC=3601449090=36. \begin{gathered} \angle BAC=360^\circ-144^\circ-90^\circ \\ {}-90^\circ=36^\circ. \end{gathered}

Thus, the correct answer is C.

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