2008 AMC 12A 第 9 题

先试着解答 2008 AMC 12A 第 9 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2008 AMC 12A 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

较老的电视屏幕宽高比为 4:34:3 也就是说,宽与高之比为 4:34:3。许多电影的宽高比不是 4:34:3。所以有时会用“信箱式”显示,也就是在屏幕顶部和底部加等高黑条,如图。假设一部电影宽高比为 2:12:1,在一台对角线为 2727 英寸的旧电视上播放。每条黑条的高度是多少英寸?

Older television screens have an aspect ratio of 4:3.4:3. That is, the ratio of the width to the height is 4:3.4:3. The aspect ratio of many movies is not 4:3,4:3, so they are sometimes shown on a television screen by "letterboxing" — darkening strips of equal height at the top and bottom of the screen, as shown. Suppose a movie has an aspect ratio of 2:12:1 and is shown on an older television screen with a 2727-inch diagonal. What is the height, in inches, of each darkened strip?

22

2.252.25

2.52.5

2.72.7

33

答案:D
知识点:勾股数比与比例
难度评级:1410
解答:

屏幕高、宽、对角线成 3:4:53:4:5,所以高度为 3527=16.2\tfrac{3}{5} \cdot 27 = 16.2 英寸,宽度为 4527=21.6\tfrac{4}{5} \cdot 27 = 21.6 英寸。

电影宽高比为 2:12:1,使用完整宽度时高度为 21.62=10.8\tfrac{21.6}{2} = 10.8 英寸。

每条黑条高度为 16.210.82=2.7 \dfrac{16.2 - 10.8}{2} = 2.7

所以正确答案是 D

Since the sides and diagonal are in ratio 3:4:5,3:4:5, the height is 3527=16.2\tfrac{3}{5} \cdot 27 = 16.2 inches and the width is 4527=21.6\tfrac{4}{5} \cdot 27 = 21.6 inches.

The movie has aspect ratio 2:1,2:1, so its height is 21.62=10.8\tfrac{21.6}{2} = 10.8 inches.

Each darkened strip therefore has height 16.210.82=2.7 \dfrac{16.2 - 10.8}{2} = 2.7 inches.

Thus, D is the correct answer.

← 第 8 题#8
完整试卷

其他年份的第 9 题