2001 AMC 12 第 7 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

一个慈善机构出售了 140140 张义演票,共收入 $2001\$2001。有些票按全价出售(全价是整数美元),其余按半价出售。全价票一共收入了多少钱?

A charity sells 140140 benefit tickets for a total of $2001.\$2001. Some tickets sell for full price (a whole dollar amount), and the rest sell for half price. How much money is raised by the full-price tickets?

$782\$782

$986\$986

$1158\$1158

$1219\$1219

$1449\$1449

答案:A
知识点:丢番图方程质因数分解极限情形界定
难度评级:1370
解答:

nn 张票以每张 pp 美元的全价出售。则 所以 p(n+140)p(n + 140) =4002= 4002 =232329= 2 \cdot 3 \cdot 23 \cdot 29np+(140n)p2=2001, np + (140 - n)\dfrac{p}{2} = 2001,

因为 0n1400 \le n \le 140, 我们需要 40024002 的一个因数满足 140n+140280140 \le n + 140 \le 280。 唯一这样的因数是 174=2329174 = 2 \cdot 3 \cdot 29, 得 n=34n = 34p=23p = 23

全价票收入为 3423=78234 \cdot 23 = 782 美元。

因此,正确答案是 A

Let nn tickets sell at full price pp dollars. Then np+(140n)p2=2001, np + (140 - n)\dfrac{p}{2} = 2001, so p(n+140)p(n + 140) =4002= 4002 =232329.= 2 \cdot 3 \cdot 23 \cdot 29.

Since 0n140,0 \le n \le 140, we need a factor of 40024002 with 140n+140280.140 \le n + 140 \le 280. The only such factor is 174=2329,174 = 2 \cdot 3 \cdot 29, giving n=34n = 34 and p=23.p = 23.

The full-price tickets raise 3423=78234 \cdot 23 = 782 dollars.

Thus, the correct answer is A.

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