2003 AMC 12A 第 15 题

先试着解答 2003 AMC 12A 第 15 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2003 AMC 12A 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

15.

如图,一个直径为 11 的半圆位于一个直径为 22 的半圆上方。小半圆内部且大半圆外部的阴影区域称为月牙形。求这个月牙形的面积。

A semicircle of diameter 11 sits at the top of a semicircle of diameter 2,2, as shown. The shaded area inside the smaller semicircle and outside the larger semicircle is called a lune. Determine the area of this lune.

16π34\dfrac{1}{6}\pi - \dfrac{\sqrt{3}}{4}

34112π\dfrac{\sqrt{3}}{4} - \dfrac{1}{12}\pi

34124π\dfrac{\sqrt{3}}{4} - \dfrac{1}{24}\pi

34+124π\dfrac{\sqrt{3}}{4} + \dfrac{1}{24}\pi

34+112π\dfrac{\sqrt{3}}{4} + \dfrac{1}{12}\pi

答案:C
知识点:扇形面积分割等边三角形
难度评级:1630
解答:

小半圆的直径是大圆半径 11 中长为 11 的弦,所以它在圆心处张成 6060^\circ

由该弦和小圆弧围成的区域等于一个面积 34\dfrac{\sqrt3}{4} 的等边三角形加上小半圆面积 12π(12)2=π8\dfrac12\pi\left(\dfrac12\right)^2=\dfrac{\pi}{8}

减去大圆的 6060^\circ 扇形面积 16π(1)2=π6\dfrac16\pi(1)^2=\dfrac{\pi}{6},得月牙面积 34+π8π6=34π24.\dfrac{\sqrt3}{4}+\dfrac{\pi}{8}-\dfrac{\pi}{6}=\dfrac{\sqrt3}{4}-\dfrac{\pi}{24}.

所以正确答案是 C

The small semicircle's diameter is a chord of length 11 in the large circle of radius 1,1, so it subtends a 6060^\circ angle at the center.

The region bounded by that chord and the small arc is an equilateral triangle of area 34\dfrac{\sqrt3}{4} topped by the small semicircle of area 12π(12)2=π8.\dfrac12\pi\left(\dfrac12\right)^2=\dfrac{\pi}{8}.

Subtracting the 6060^\circ sector of the large circle, 16π(1)2=π6,\dfrac16\pi(1)^2=\dfrac{\pi}{6}, gives the lune area 34+π8π6=34π24.\dfrac{\sqrt3}{4}+\dfrac{\pi}{8}-\dfrac{\pi}{6}=\dfrac{\sqrt3}{4}-\dfrac{\pi}{24}.

Thus, the correct answer is C.

← 第 14 题#14
完整试卷

其他年份的第 15 题