2020 AMC 12A 第 3 题

先试着解答 2020 AMC 12A 第 3 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2020 AMC 12A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

3.

一名司机以每小时 6060 英里的速度行驶 22 小时,在此期间她的汽车每加仑汽油可行驶 3030 英里。她每英里获得 $0.50\$0.50 报酬,唯一开销是每加仑 $2.00\$2.00 的汽油。扣除这项开销后,她每小时的净报酬是多少美元?
A driver travels for 22 hours at 6060 miles per hour, during which her car gets 3030 miles per gallon of gasoline. She is paid $0.50\$0.50 per mile, and her only expense is gasoline at $2.00\$2.00 per gallon. What is her net rate of pay, in dollars per hour, after this expense?
2020
2222
2424
2525
2626
答案:E
知识点:速率单位换算
小提示:
22 小时内她行驶 120120 英里;求出这段距离的报酬和汽油费用
In 22 hours she drives 120120 miles; find her pay and her gasoline cost for that distance
大提示:
用净收入除以 22 小时,得到每小时的报酬
Divide the net earnings by the 22 hours to get the rate per hour
解答:
22 小时内她行驶 120120 英里,收入为 120⋅$0.50=$60120 \cdot \$0.50 = \$60。
她用掉 120÷30=4120 \div 30 = 4 加仑汽油,花费 4⋅$2.00=$84 \cdot \$2.00 = \$8。
净收入为 $60−$8=$52\$60 - \$8 = \$52,因此每小时为 $52÷2=$26\$52 \div 2 = \$26。
因此,正确答案是 E。
In 22 hours she drives 120120 miles, earning 120⋅$0.50=$60.120 \cdot \$0.50 = \$60.
She uses 120÷30=4120 \div 30 = 4 gallons, costing 4⋅$2.00=$8.4 \cdot \$2.00 = \$8.
Her net earnings are $60−$8=$52,\$60 - \$8 = \$52, so her rate is $52÷2=$26\$52 \div 2 = \$26 per hour.
Thus, E is the correct answer.
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