2021 AMC 12B Fall Problem 3

Below is the professionally curated solution for Problem 3 of the 2021 AMC 12B Fall, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Fall solutions, or check the answer key.

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Concepts:absolute valuecasework

Difficulty rating: 1090

3.

At noon on a certain day, Minneapolis is NN degrees warmer than St. Louis. At 4:004{:}00 the temperature in Minneapolis has fallen by 55 degrees while the temperature in St. Louis has risen by 33 degrees, at which time the temperatures in the two cities differ by 22 degrees. What is the product of all possible values of N?N?

1010

3030

6060

100100

120120

Solution:

At noon the gap is N.N. Minneapolis then loses 55 degrees and St. Louis gains 3,3, so the gap changes by 8.8. The new absolute difference is N8=2.|N - 8| = 2.

This gives N=10N = 10 or N=6,N = 6, whose product is 60.60.

Thus, the correct answer is C.

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