2019 AMC 12A Problem 3
Below is the professionally curated solution for Problem 3 of the 2019 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 12A solutions, or check the answer key.
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Difficulty rating: 1020
3.
A box contains red balls, green balls, yellow balls, blue balls, white balls, and black balls. What is the minimum number of balls that must be drawn from the box without replacement to guarantee that at least balls of a single color will be drawn?
Solution:
In the worst case, we draw each of red, green, and yellow, plus all of the blue white and black without reaching of any color.
That is balls.
The next ball must complete a set of so balls are needed.
Thus, the correct answer is B.
Problem 3 in Other Years
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