2019 AMC 12A Problem 4
Below is the professionally curated solution for Problem 4 of the 2019 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 12A solutions, or check the answer key.
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Difficulty rating: 1170
4.
What is the greatest number of consecutive integers whose sum is
Solution:
Negative integers are allowed. The integers from to sum to so the integers from to sum to
This run has integers, and no longer run can work.
Thus, the correct answer is D.
Problem 4 in Other Years
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