2018 AMC 12B 第 11 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

11.

一个以正方形为底的封闭盒子,要用一张正方形包装纸包装。盒子居中放在包装纸上,底面顶点落在正方形纸的中线上, 如左图所示。包装纸四个角将沿侧面向上折起,并在盒子顶部中心点 AA 处相遇,如右图所示。 盒子底边长为 ww,高为 hh。包装纸的面积是多少?

A closed box with a square base is to be wrapped with a square sheet of wrapping paper. The box is centered on the wrapping paper with the vertices of the base lying on the midlines of the square sheet of paper, as shown in the figure on the left. The four corners of the wrapping paper are to be folded up over the sides and brought together to meet at the center of the top of the box, point AA in the figure on the right. The box has base length ww and height h.h. What is the area of the sheet of wrapping paper?

2(w+h)22(w+h)^2

(w+h)22\dfrac{(w+h)^2}{2}

2w2+4wh2w^2+4wh

2w22w^2

w2hw^2h

答案:A
知识点:特殊直角三角形面积
难度评级:1760
解答:

沿着折线从纸角到盒顶中心看,纸角到纸中心的距离为 w2+h+w2=w+h. \dfrac{w}{2}+h+\dfrac{w}{2}=w+h.

这段是 4545-4545-9090 三角形的一条直角边,其斜边是正方形包装纸的一整条边, 所以边长为 2(w+h)\sqrt2\,(w+h)

包装纸面积为 (2(w+h))2=2(w+h)2\left(\sqrt2\,(w+h)\right)^2=2(w+h)^2

所以正确答案是 A

Following a fold from a corner of the paper to the center of the box top, the distance from a corner of the sheet to its center is w2+h+w2=w+h. \dfrac{w}{2}+h+\dfrac{w}{2}=w+h.

That segment is a leg of a 4545-4545-9090 triangle whose hypotenuse is a full side of the square sheet, so the side length is 2(w+h).\sqrt2\,(w+h).

The area of the sheet is (2(w+h))2=2(w+h)2.\left(\sqrt2\,(w+h)\right)^2=2(w+h)^2.

Thus, the correct answer is A.

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