1999 AMC 12 Problem 11

Below is the professionally curated solution for Problem 11 of the 1999 AMC 12, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 12 solutions, or check the answer key.

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Concepts:digitscounting integers in a range

Difficulty rating: 1450

11.

The student lockers at Olympic High are numbered consecutively beginning with locker number 1.1. The plastic digits used to number the lockers cost 22 cents apiece. Thus, it costs 22 cents to label locker number 99 and 44 cents to label locker number 10.10. If it costs $137.94\$137.94 to label all the lockers, how many lockers are there at the school?

20012001

20102010

21002100

27262726

68976897

Solution:

Labeling costs $137.94/$0.02=6897\$137.94 / \$0.02 = 6897 digits. Lockers 11-99 use 99 digits, lockers 1010-9999 use 290=1802 \cdot 90 = 180 digits, and lockers 100100-999999 use 3900=27003 \cdot 900 = 2700 digits.

The remaining digits number 689727001809=4008,6897 - 2700 - 180 - 9 = 4008, which label 4008/4=10024008 / 4 = 1002 four-digit lockers. In all there are 999+1002=2001999 + 1002 = 2001 lockers.

Thus, the correct answer is A.

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