2006 AMC 12B Problem 11

Below is the professionally curated solution for Problem 11 of the 2006 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 12B solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:mixtureratio and proportion

Difficulty rating: 1510

11.

Joe and JoAnn each bought 1212 ounces of coffee in a 1616-ounce cup. Joe drank 22 ounces of his coffee and then added 22 ounces of cream. JoAnn added 22 ounces of cream, stirred the coffee well, and then drank 22 ounces. What is the resulting ratio of the amount of cream in Joe's coffee to that in JoAnn's coffee?

67\dfrac{6}{7}

1314\dfrac{13}{14}

11

1413\dfrac{14}{13}

76\dfrac{7}{6}

Solution:

Joe adds the cream last, so his cup holds all 22 ounces of cream.

JoAnn's cup has 1414 ounces of mixture containing 22 ounces of cream. Drinking 22 ounces removes a fraction 214\tfrac{2}{14} of everything, leaving 21214=1272 \cdot \frac{12}{14} = \frac{12}{7} ounces of cream.

The ratio is 212/7=1412=76.\frac{2}{\,12/7\,} = \frac{14}{12} = \frac{7}{6}.

Thus, the correct answer is E.

Problem 11 in Other Years