2014 AMC 12A Problem 11

Below is the professionally curated solution for Problem 11 of the 2014 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 12A solutions, or check the answer key.

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Concepts:distance rate and timesystem of equations

Difficulty rating: 1440

11.

David drives from his home to the airport to catch a flight. He drives 3535 miles in the first hour, but realizes that he will be 11 hour late if he continues at this speed. He increases his speed by 1515 miles per hour for the rest of the way to the airport and arrives 3030 minutes early. How many miles is the airport from his home?

140140

175175

210210

245245

280280

Solution:

Let dd be the remaining distance after one hour and tt the remaining time until the flight. At 3535 mph he would be an hour late, so d=35(t+1).d=35(t+1). At 5050 mph he is half an hour early, so d=50(t12).d=50\left(t-\tfrac12\right).

Setting these equal gives 35t+35=50t25,35t+35=50t-25, so t=4t=4 and d=175.d=175.

The total distance is 175+35=210175+35=210 miles.

Thus, the correct answer is C.

Problem 11 in Other Years