2012 AMC 12B 第 7 题

先试着解答 2012 AMC 12B 第 7 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2012 AMC 12B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

小灯泡按红、红、绿、绿、绿、红、红、绿、绿、绿这样的顺序挂在一根绳子上,相邻灯泡相距 66 英寸,并一直重复 22 个红灯后接 33 个绿灯的模式。第 33 个红灯和第 2121 个红灯相距多少英尺?
注:11 英尺等于 1212 英寸。
Small lights are hung on a string 66 inches apart in the order red, red, green, green, green, red, red, green, green, green, and so on continuing this pattern of 22 red lights followed by 33 green lights. How many feet separate the 33rd red light and the 2121st red light?
Note: 11 foot is equal to 1212 inches.
1818
18.518.5
2020
20.520.5
22.522.5
答案:E
知识点:找规律单位换算
小提示:
把灯泡按每 55 个一组分组:两个红灯,三个绿灯
Group the lights into repeating blocks of 55 (two red, three green)
大提示:
第 33 个红灯是第 22 组的开头,第 2121 个红灯是第 1111 组的开头
The 33rd red light starts block 22 and the 2121st red light starts block 1111
解答:
灯泡按每 55 个一组重复,所以相邻两组的开头相距 5⋅6=305\cdot6=30 英寸,即 2.52.5 英尺。
每一组的开头都是一个奇数编号的红灯。第 33 个红灯是第 22 组的开头,第 2121 个红灯是第 1111 组的开头。
它们之间的距离是 (11−2)⋅2.5=22.5(11-2)\cdot2.5=22.5 英尺。
因此正确答案是 E。
The lights repeat in blocks of 5,5, so consecutive blocks start 5⋅6=305\cdot6=30 inches, or 2.52.5 feet, apart.
Each block has one odd-numbered red light beginning it. The 33rd red light begins the 22nd block and the 2121st red light begins the 1111th block.
The distance between them is (11−2)⋅2.5=22.5(11-2)\cdot2.5=22.5 feet.
Thus, the correct answer is E.
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