2012 AMC 12B 第 7 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

小灯泡按红、红、绿、绿、绿、红、红、绿、绿、绿这样的顺序挂在一根绳子上,相邻灯泡相距 66 英寸,并一直重复 22 个红灯后接 33 个绿灯的模式。第 33 个红灯和第 2121 个红灯相距多少英尺?

注:11 英尺等于 1212 英寸。

Small lights are hung on a string 66 inches apart in the order red, red, green, green, green, red, red, green, green, green, and so on continuing this pattern of 22 red lights followed by 33 green lights. How many feet separate the 33rd red light and the 2121st red light?

Note: 11 foot is equal to 1212 inches.

1818

18.518.5

2020

20.520.5

22.522.5

答案:E
知识点:找规律单位换算
难度评级:1270
解答:

灯泡按每 55 个一组重复,所以相邻两组的开头相距 56=305\cdot6=30 英寸,即 2.52.5 英尺。

每一组的开头都是一个奇数编号的红灯。第 33 个红灯是第 22 组的开头,第 2121 个红灯是第 1111 组的开头。

它们之间的距离是 (112)2.5=22.5(11-2)\cdot2.5=22.5 英尺。

因此正确答案是 E

The lights repeat in blocks of 5,5, so consecutive blocks start 56=305\cdot6=30 inches, or 2.52.5 feet, apart.

Each block has one odd-numbered red light beginning it. The 33rd red light begins the 22nd block and the 2121st red light begins the 1111th block.

The distance between them is (112)2.5=22.5(11-2)\cdot2.5=22.5 feet.

Thus, the correct answer is E.

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