2007 AMC 12A 第 13 题

先试着解答 2007 AMC 12A 第 13 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2007 AMC 12A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

一块奶酪位于坐标平面上的 (12,10)(12,10)。一只老鼠在 (4,−2)(4,-2),并沿直线 y=−5x+18y=-5x+18 向上跑。在点 (a,b)(a,b) 处,老鼠开始离奶酪越来越远,而不是越来越近。求 a+ba+b?
A piece of cheese is located at (12,10)(12,10) in a coordinate plane. A mouse is at (4,−2)(4,-2) and is running up the line y=−5x+18.y=-5x+18. At the point (a,b)(a,b) the mouse starts getting farther from the cheese rather than closer to it. What is a+b?a+b?
66
1010
1414
1818
2222
答案:B
知识点:坐标几何斜率
小提示:
直线上距离奶酪最近的点是从奶酪向该直线作垂线的垂足。
The closest point on the line is the foot of the perpendicular from the cheese
大提示:
过 (12,10)(12,10) 的垂线斜率为 15\tfrac15;求它与 y=−5x+18y=-5x+18 的交点。
The perpendicular through (12,10)(12,10) has slope 15\tfrac15; intersect it with y=−5x+18y=-5x+18
解答:
老鼠在从 (12,10)(12,10) 到该直线的垂足处最接近奶酪。
这条垂线斜率为 15\tfrac15,所以方程为 y=10+15(x−12)=15x+385y=10+\tfrac15(x-12)=\tfrac15 x+\tfrac{38}{5}。
令 15x+385=−5x+18\tfrac15 x+\tfrac{38}{5}=-5x+18,得 x=2x=2 且 y=8y=8。因此 (a,b)=(2,8)(a,b)=(2,8),a+b=10a+b=10。
因此,正确答案是 B。
The mouse is closest to the cheese at the foot of the perpendicular from (12,10)(12,10) to the line.
This perpendicular has slope 15,\tfrac15, so its equation is y=10+15(x−12)=15x+385.y=10+\tfrac15(x-12)=\tfrac15 x+\tfrac{38}{5}.
Setting 15x+385=−5x+18\tfrac15 x+\tfrac{38}{5}=-5x+18 gives x=2x=2 and y=8.y=8. Thus (a,b)=(2,8)(a,b)=(2,8) and a+b=10.a+b=10.
Thus, the correct answer is B.
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