2000 AMC 12 Problem 13

Below is the professionally curated solution for Problem 13 of the 2000 AMC 12, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 12 solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:fractionlinear equationbounding to limit cases

Difficulty rating: 1710

13.

One morning each member of Angela's family drank an 88-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup, but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family?

33

44

55

66

77

Solution:

Measure amounts in 88-ounce cups, so Angela's cup holds cc coffee and mm milk with c+m=1.c + m = 1.

Since Angela drank a sixth of the coffee, the total coffee is 6c6c; since she drank a quarter of the milk, the total milk is 4m.4m. The number of people equals the total number of cups, 6c+4m=6c+4(1c)=4+2c. 6c + 4m = 6c + 4(1 - c) = 4 + 2c.

This is an integer only when 2c2c is an integer, and since 0<c<10 \lt c \lt 1 this forces c=12,c = \tfrac12, giving 4+1=54 + 1 = 5 people.

Thus, the correct answer is C.

Problem 13 in Other Years