2006 AMC 12B 第 7 题

先试着解答 2006 AMC 12B 第 7 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2006 AMC 12B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

Lopez 先生和 Lopez 太太有两个孩子。他们上家庭汽车时,两个人坐在前排,另外两个人坐在后排。Lopez 先生或 Lopez 太太必须坐在驾驶座。共有多少种座位安排?
Mr. and Mrs. Lopez have two children. When they get into their family car, two people sit in the front, and the other two sit in the back. Either Mr. Lopez or Mrs. Lopez must sit in the driver’s seat. How many seating arrangements are possible?
44
1212
1616
2424
4848
答案:B
知识点:乘法原理有限制的排列
小提示:
按顺序安排座位:驾驶座、副驾驶座,然后是两个后排座位
Fill the seats in order: driver, then front passenger, then the two back seats
大提示:
驾驶座有 22 种选择,副驾驶座有 33 种选择,后排有 22 种顺序
There are 22 choices for the driver and 33 for the front passenger, then 22 orders in back
解答:
驾驶员是两位父母之一:有 22 种选择。
剩下的 33 人中任意一人可以坐副驾驶座,最后 22 人坐后排,有 22 种顺序。
总数为 2⋅3⋅2=122 \cdot 3 \cdot 2 = 12。
因此,正确答案是 B。
The driver is one of the two parents: 22 choices.
Any of the remaining 33 people can sit in the front passenger seat, and the last 22 people fill the back in 22 orders.
The total is 2⋅3⋅2=12.2 \cdot 3 \cdot 2 = 12.
Thus, the correct answer is B.
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