2000 AMC 12 第 13 题

先试着解答 2000 AMC 12 第 13 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2000 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

某天早上,Angela 家的每个人都喝了一杯 88-盎司的咖啡牛奶混合饮品。每杯中咖啡和牛奶的量可能不同,但都不为零。Angela 喝掉了全家牛奶总量的四分之一和咖啡总量的六分之一。这个家庭有多少人?
One morning each member of Angela’s family drank an 88-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup, but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family?
33
44
55
66
77
答案:C
知识点:分数一次方程极限情形界定
小提示:
设 Angela 自己的一杯中有 cc 杯咖啡和 mm 杯牛奶,且 c+m=1c + m = 1。
Suppose Angela’s own cup contains cc units of coffee and mm units of milk with c+m=1c + m = 1
大提示:
则全家共有 6c6c 杯咖啡和 4m4m 杯牛奶,所以人数为 6c+4m6c + 4m。
Then the family total is 6c6c coffee and 4m4m milk, so the number of people is 6c+4m6c + 4m
解答:
以 88-盎司的一杯为单位计量,所以 Angela 的杯中有 cc 杯咖啡和 mm 杯牛奶,且 c+m=1c + m = 1。
因为 Angela 喝掉了咖啡总量的六分之一,所以咖啡总量为 6c6c;因为她喝掉了牛奶总量的四分之一,所以牛奶总量为 4m4m。人数等于总杯数:6c+4m=6c+4(1−c)=4+2c。 \begin{aligned} 6c + 4m &= 6c + 4(1 - c) \\ &= 4 + 2c \end{aligned}\text{。}
这必须是整数,所以 2c2c 是整数。又因 0<c<10 \lt c \lt 1,只能有 c=12c = \tfrac12,从而人数为 4+1=54 + 1 = 5。
因此,正确答案是 C。
Measure amounts in 88-ounce cups, so Angela’s cup holds cc coffee and mm milk with c+m=1.c + m = 1.
Since Angela drank a sixth of the coffee, the total coffee is 6c6c; since she drank a quarter of the milk, the total milk is 4m.4m. The number of people equals the total number of cups, 6c+4m=6c+4(1−c)=4+2c. \begin{aligned} 6c + 4m &= 6c + 4(1 - c) \\ &= 4 + 2c. \end{aligned}
This is an integer only when 2c2c is an integer, and since 0<c<10 \lt c \lt 1 this forces c=12,c = \tfrac12, giving 4+1=54 + 1 = 5 people.
Thus, the correct answer is C.
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.