2000 AMC 12 第 13 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

某天早上,Angela 家的每个人都喝了一杯 88-盎司的咖啡牛奶混合饮品。每杯中咖啡和牛奶的量可能不同,但都不为零。Angela 喝掉了全家牛奶总量的四分之一和咖啡总量的六分之一。这个家庭有多少人?

One morning each member of Angela's family drank an 88-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup, but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family?

33

44

55

66

77

答案:C
知识点:分数一次方程极限情形界定
难度评级:1710
解答:

88-盎司的一杯为单位计量,所以 Angela 的杯中有 cc 杯咖啡和 mm 杯牛奶,且 c+m=1c + m = 1

因为 Angela 喝掉了咖啡总量的六分之一,所以咖啡总量为 6c6c;因为她喝掉了牛奶总量的四分之一,所以牛奶总量为 4m4m。 人数等于总杯数: 6c+4m=6c+4(1c)=4+2c. \begin{aligned} 6c + 4m &= 6c + 4(1 - c) \\ &= 4 + 2c. \end{aligned}

这必须是整数,所以 2c2c 是整数。又因 0<c<10 \lt c \lt 1,只能有 c=12c = \tfrac12, 从而人数为 4+1=54 + 1 = 5

因此,正确答案是 C

Measure amounts in 88-ounce cups, so Angela's cup holds cc coffee and mm milk with c+m=1.c + m = 1.

Since Angela drank a sixth of the coffee, the total coffee is 6c6c; since she drank a quarter of the milk, the total milk is 4m.4m. The number of people equals the total number of cups, 6c+4m=6c+4(1c)=4+2c. \begin{aligned} 6c + 4m &= 6c + 4(1 - c) \\ &= 4 + 2c. \end{aligned}

This is an integer only when 2c2c is an integer, and since 0<c<10 \lt c \lt 1 this forces c=12,c = \tfrac12, giving 4+1=54 + 1 = 5 people.

Thus, the correct answer is C.

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