Question

令 $n$ 为大于 $1$ 、没有小于 $10$ 的素因数的最小合数。则

Let $n$ be the smallest nonprime integer greater than $1$ with no prime factor less than $10.$ Then

$100\lt n\le110$

$110\lt n\le120$

$120\lt n\le130$

$130\lt n\le140$

$140\lt n\le150$

允许的最小素因数为 $11$

The smallest permitted prime factor is $11$

要得到最小合数，使用两个最小的允许素因数

To make the smallest composite, use the two smallest permitted prime factors

$n$ 的每个素因数都至少为 $11$ 。满足这一性质的最小合数是 $11\cdot11=121$ ，它位于 $120\lt n\le130$ 内。

所以正确答案是 C。

Every prime factor of $n$ is at least $11.$ The smallest composite with that property is $11\cdot11=121,$ which lies in $120\lt n\le130.$

Therefore, the correct answer is C.