2015 AMC 12B 第 3 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

3.

Isaac 写下了某个整数两次,另一个整数三次。这五个数的和为 100100, 并且其中一个数是 2828。 另一个数是多少?

Isaac has written down one integer two times and another integer three times. The sum of the five numbers is 100,100, and one of the numbers is 28.28. What is the other number?

88

1111

1414

1515

1818

答案:A
知识点:丢番图方程整除性
难度评级:1050
解答:

写作 2x+3y=1002x + 3y = 100。 如果 2828 被写了两次,则 3y=10056=443y = 100 - 56 = 44, 这不是 33 的倍数。

所以 2828 被写了三次:2x=10084=162x = 100 - 84 = 16, 得 x=8x = 8

因此,正确选项是 A

Write 2x+3y=100.2x + 3y = 100. If 2828 were written twice, then 3y=10056=44,3y = 100 - 56 = 44, which is not a multiple of 3.3.

So 2828 is written three times: 2x=10084=16,2x = 100 - 84 = 16, giving x=8.x = 8.

Thus, the correct answer is A.

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