2013 AMC 12B 第 7 题

先试着解答 2013 AMC 12B 第 7 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2013 AMC 12B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

7.

Jo 和 Blair 轮流从 11 开始数,每次比对方上一轮说到的最后一个数多说一个数。Jo 先说“11”,所以 Blair 接着说“11、22”。然后 Jo 说“11、22、33”,依此类推。说出的第 5353 个数是什么?
Jo and Blair take turns counting from 11 to one more than the last number said by the other person. Jo starts by saying “11”, so Blair follows by saying “1,1, 22”. Jo then says “1,1, 2,2, 33”, and so on. What is the 5353rd number said?
22
33
55
66
88
答案:E
知识点:三角形数
小提示:
以 nn 结尾的一轮,就是某人说 1,2,…,n1, 2, \ldots, n。
The turn that ends at nn consists of someone saying 1,2,…,n1, 2, \ldots, n
大提示:
到以 nn 结尾的那一轮结束时,总共说了 12n(n+1)\tfrac12 n(n+1) 个数。
After the turn ending at n,n, a total of 12n(n+1)\tfrac12 n(n+1) numbers have been said
解答:
到数到 nn 的那一轮结束时,共说了 1+2+⋯+n=12n(n+1)1 + 2 + \cdots + n = \tfrac12 n(n+1) 个数。当 n=9n = 9 时,这个总数为 4545。下一轮从 1,2,…1, 2, \ldots 开始,所以第 5353 个数是这一轮的第 88 个数,即 88。正确答案是 E。
After the turn that counts up to n,n, exactly 1+2+⋯+n=12n(n+1)1 + 2 + \cdots + n = \tfrac12 n(n+1) numbers have been said. For n=9n = 9 that is 45.45. The next turn starts 1,2,…,1, 2, \ldots, so the 5353rd number is the 88th number of that turn, namely 8.8. Thus, the correct answer is E.
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