2004 AMC 12B 第 11 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

11.

代数课上的所有学生都参加了一次满分 100100 分的考试。五名学生得了 100100, 分,每名学生至少得 6060, 分,平均分为 7676。这个班最少可能有多少名学生?

All the students in an algebra class took a 100100-point test. Five students scored 100,100, each student scored at least 60,60, and the mean score was 76.76. What is the smallest possible number of students in the class?

1010

1111

1212

1313

1414

答案:D
知识点:平均数极限情形界定
难度评级:1440
解答:

每个 100100 分比平均分 76762424 分,所以五个学生共高出 120120 分。这些必须由低于平均分的分数抵消,而每个剩余学生最多低 7660=1676 - 60 = 16 分。因此至少需要 12016=7.5\dfrac{120}{16} = 7.5,即 88 名额外学生,总数为 1313。五个 100100 分和八个 6161 分可以达到这一情况。

因此正确答案是 D

Each score of 100100 is 2424 above the mean, so the five contribute 120120 points above 76.76. These must be balanced by points below the mean, and each remaining student is at most 7660=1676 - 60 = 16 below. So at least 12016=7.5,\dfrac{120}{16} = 7.5, hence 88 more students are needed, for a total of 13.13. Five 100100s and eight 6161s achieve this.

Thus, the correct answer is D.

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