2025 AMC 12A 第 3 题

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3.

一队学生将和一队老师进行知识竞赛。学生和老师总共有 1515 人。Ash 是其中一名学生的表亲,他想加入比赛。如果 Ash 加入学生队,该队的平均年龄会从 1212 岁增加到 1414 岁。如果 Ash 加入老师队,该队的平均年龄会从 5555 岁降低到 5252 岁。Ash 多少岁?

A team of students is going to compete against a team of teachers in a trivia contest. The total number of students and teachers is 15.15. Ash, a cousin of one of the students, wants to join the contest. If Ash plays with the students, the average age on that team will increase from 1212 to 14.14. If Ash plays with the teachers, the average age on that team will decrease from 5555 to 52.52. How old is Ash?

2828

2929

3030

3232

3333

答案:A
知识点:方程组平均数年龄问题
难度评级:1130
解答:

设学生人数为 ss,Ash 的年龄为 aa。学生年龄总和为 12s12s, 加入 Ash 后得到 12s+a=14(s+1)    a=2s+14. \begin{aligned} 12s + a &= 14(s+1) \\ &\implies a = 2s + 14. \end{aligned}

老师有 15s15 - s 人,年龄总和为 55(15s)55(15-s), 加入 Ash 后得到 55(15s)+a=52(16s)    a=3s+7. \begin{aligned} 55(15-s) + a &= 52(16-s) \\ &\implies a = 3s + 7. \end{aligned}

2s+14=3s+72s+14 = 3s+7,得 s=7s = 7, 所以 a=2(7)+14=28a = 2(7)+14 = 28

因此,正确答案是 A

Let ss be the number of students and aa be Ash's age. The students' ages total 12s,12s, and adding Ash gives 12s+a=14(s+1)    a=2s+14. \begin{aligned} 12s + a &= 14(s+1) \\ &\implies a = 2s + 14. \end{aligned}

There are 15s15 - s teachers with ages totaling 55(15s),55(15-s), and adding Ash gives 55(15s)+a=52(16s)    a=3s+7. \begin{aligned} 55(15-s) + a &= 52(16-s) \\ &\implies a = 3s + 7. \end{aligned}

Setting 2s+14=3s+72s+14 = 3s+7 gives s=7,s = 7, so a=2(7)+14=28.a = 2(7)+14 = 28.

Thus, the correct answer is A.

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