2013 AMC 12A 第 3 题

先试着解答 2013 AMC 12A 第 3 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2013 AMC 12A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

3.

一束花包含粉玫瑰、红玫瑰、粉康乃馨和红康乃馨。粉色花中有三分之一是玫瑰,红色花中有四分之三是康乃馨,且所有花中有十分之六是粉色。所有花中有百分之几是康乃馨?
A flower bouquet contains pink roses, red roses, pink carnations, and red carnations. One third of the pink flowers are roses, three fourths of the red flowers are carnations, and six tenths of the flowers are pink. What percent of the flowers are carnations?
1515
3030
4040
6060
7070
答案:E
知识点:分数百分数
小提示:
所有花中十分之六是粉色,十分之四是红色
Six tenths of the flowers are pink and four tenths are red
大提示:
粉色花的三分之二和红色花的四分之三是康乃馨;把两部分相加
Two thirds of the pink and three fourths of the red are carnations; add the two amounts
解答:
所有花中十分之六是粉色,十分之四是红色。因为粉色花中三分之二是康乃馨,所以粉康乃馨占全部花的 23⋅610=410\tfrac{2}{3}\cdot\tfrac{6}{10} = \tfrac{4}{10}。
因为红色花中四分之三是康乃馨,所以红康乃馨占全部花的 34⋅410=310\tfrac{3}{4}\cdot\tfrac{4}{10} = \tfrac{3}{10}。康乃馨合计占 410+310=710=70%\tfrac{4}{10} + \tfrac{3}{10} = \tfrac{7}{10} = 70\%。
因此,正确答案是 E。
Six tenths of the flowers are pink and four tenths are red. Since two thirds of the pink flowers are carnations, pink carnations make up 23⋅610=410\tfrac{2}{3}\cdot\tfrac{6}{10} = \tfrac{4}{10} of the flowers.
Since three fourths of the red flowers are carnations, red carnations make up 34⋅410=310\tfrac{3}{4}\cdot\tfrac{4}{10} = \tfrac{3}{10} of the flowers. Together the carnations are 410+310=710=70%.\tfrac{4}{10} + \tfrac{3}{10} = \tfrac{7}{10} = 70\%.
Thus, the correct answer is E.
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